derivative f(x)=(2x+6x^2)/((1+6x)^2)

Lösung

ableitung von

f (x) = \frac{2 x + 6 x ^{2}}{( 1 + 6 x ) ^{2}}

\frac{2}{( 1 + 6 x ) ^{3}}

Schritte zur Lösung

\frac{d}{d x} (\frac{2 x + 6 x ^{2}}{( 1 + 6 x ) ^{2}})

Wende die Quotientenregel an:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 x + 6 x ^{2} ) ( 1 + 6 x ) ^{2} - \frac{d}{d x} ( ( 1 + 6 x ) ^{2} ) ( 2 x + 6 x ^{2} )}{( ( 1 + 6 x ) ^{2} ) ^{2}}

\frac{d}{d x} (2 x + 6 x^{2}) = 2 + 12 x

\frac{d}{d x} ((1 + 6 x)^{2}) = 12 (1 + 6 x)

= \frac{( 2 + 12 x ) ( 1 + 6 x ) ^{2} - 12 ( 1 + 6 x ) ( 2 x + 6 x ^{2} )}{( ( 1 + 6 x ) ^{2} ) ^{2}}

Vereinfache

\frac{( 2 + 12 x ) ( 1 + 6 x ) ^{2} - 12 ( 1 + 6 x ) ( 2 x + 6 x ^{2} )}{( ( 1 + 6 x ) ^{2} ) ^{2}} : \frac{2}{( 1 + 6 x ) ^{3}}

= \frac{2}{( 1 + 6 x ) ^{3}}

\int \frac{x + 9}{x ^{2} + 8 x + 20} d x

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