What is the tangent of f(x)=sqrt(x^2+3x),(1,2) ?

The tangent of f(x)=sqrt(x^2+3x),(1,2) is y= 5/4 x+3/4

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tangent of f(x)=sqrt(x^2+3x),(1,2)

tangent of

f (x) = x^{2} + 3 x, (1, 2)

y = \frac{5}{4} x + \frac{3}{4}

Solution steps

Find the slope of

f (x) = x^{2} + 3 x : \frac{df ( x )}{d x} = \frac{2 x + 3}{2 x ^{2} + 3 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{5}{4}

Find the line with slope m=

\frac{5}{4}

and passing through

(1, 2) : y = \frac{5}{4} x + \frac{3}{4}

y = \frac{5}{4} x + \frac{3}{4}

What is the tangent of f(x)=sqrt(x^2+3x),(1,2) ?
The tangent of f(x)=sqrt(x^2+3x),(1,2) is y= 5/4 x+3/4