What is the limit as x approaches 0 of (e^{8x}-1)/x ?

The limit as x approaches 0 of (e^{8x}-1)/x is 8

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limit as x approaches 0 of (e^{8x}-1)/x

x \to 0 lim (\frac{e ^{8 x} - 1}{x})

8

Solution steps

x \to 0 lim (\frac{e ^{8 x} - 1}{x})

Apply L'Hopital's Rule

= x \to 0 lim (\frac{8 e ^{8 x}}{1})

Plug in the value

x = 0

= \frac{8 e ^{8 \cdot 0}}{1}

Simplify

= 8

What is the limit as x approaches 0 of (e^{8x}-1)/x ?
The limit as x approaches 0 of (e^{8x}-1)/x is 8