limit as h approaches 0 of (sin(2h))/(5h^2+7h)

Lösung

h \to 0 lim (\frac{sin ( 2 h )}{5 h ^{2} + 7 h})

\frac{2}{7}

Dezimale

0.28571 \dots

Schritte zur Lösung

h \to 0 lim (\frac{sin ( 2 h )}{5 h ^{2} + 7 h})

Wende das L'Hopital Theorem an

= h \to 0 lim (\frac{cos ( 2 h ) \cdot 2}{10 h + 7})

Setze den Wert

h = 0

ein

= \frac{cos ( 2 \cdot 0 ) \cdot 2}{10 \cdot 0 + 7}

Vereinfache

\frac{cos ( 2 \cdot 0 ) \cdot 2}{10 \cdot 0 + 7} : \frac{2}{7}

= \frac{2}{7}

x \to - 2 lim ([f (x) + 5 g (x)])

x \to a lim ((x^{2}) + a^{2})

x \to 0 lim (\frac{x + 4}{x ^{2}})

x \to 1 lim (3 x^{3})

x \to 0 - lim (\frac{1}{x} - csc (x))