What is the derivative of sin(2x^3-3) ?

The derivative of sin(2x^3-3) is cos(2x^3-3)*6x^2

What is the first derivative of sin(2x^3-3) ?

The first derivative of sin(2x^3-3) is cos(2x^3-3)*6x^2

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\frac{d}{d x} (sin (2 x^{3} - 3))

cos (2 x^{3} - 3) \cdot 6 x^{2}

Solution steps

\frac{d}{d x} (sin (2 x^{3} - 3))

Apply the chain rule:

cos (2 x^{3} - 3) \frac{d}{d x} (2 x^{3} - 3)

= cos (2 x^{3} - 3) \frac{d}{d x} (2 x^{3} - 3)

\frac{d}{d x} (2 x^{3} - 3) = 6 x^{2}

= cos (2 x^{3} - 3) \cdot 6 x^{2}

What is the derivative of sin(2x^3-3) ?
The derivative of sin(2x^3-3) is cos(2x^3-3)*6x^2
What is the first derivative of sin(2x^3-3) ?
The first derivative of sin(2x^3-3) is cos(2x^3-3)*6x^2