What is the integral of xsin(x^2+4) ?

The integral of xsin(x^2+4) is -1/2 cos(x^2+4)+C

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integral of xsin(x^2+4)

\int x sin (x^{2} + 4) d x

- \frac{1}{2} cos (x^{2} + 4) + C

Solution steps

\int x sin (x^{2} + 4) d x

Apply u-substitution

= \int \frac{sin ( u )}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{2} (- cos (u))

Substitute back

u = x^{2} + 4

= \frac{1}{2} (- cos (x^{2} + 4))

Simplify

= - \frac{1}{2} cos (x^{2} + 4)

Add a constant to the solution

= - \frac{1}{2} cos (x^{2} + 4) + C

What is the integral of xsin(x^2+4) ?
The integral of xsin(x^2+4) is -1/2 cos(x^2+4)+C