What is the derivative of y=(2x^2-3)^2 ?

The derivative of y=(2x^2-3)^2 is 8x(2x^2-3)

What is the first derivative of y=(2x^2-3)^2 ?

The first derivative of y=(2x^2-3)^2 is 8x(2x^2-3)

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derivative of

y = (2 x^{2} - 3)^{2}

8 x (2 x^{2} - 3)

Solution steps

\frac{d}{d x} ((2 x^{2} - 3)^{2})

Apply the chain rule:

2 (2 x^{2} - 3) \frac{d}{d x} (2 x^{2} - 3)

= 2 (2 x^{2} - 3) \frac{d}{d x} (2 x^{2} - 3)

\frac{d}{d x} (2 x^{2} - 3) = 4 x

= 2 (2 x^{2} - 3) \cdot 4 x

Simplify

= 8 x (2 x^{2} - 3)

What is the derivative of y=(2x^2-3)^2 ?
The derivative of y=(2x^2-3)^2 is 8x(2x^2-3)
What is the first derivative of y=(2x^2-3)^2 ?
The first derivative of y=(2x^2-3)^2 is 8x(2x^2-3)