sum from k=0 to infinity of (-5/6)^k

Lösung

k = 0 \sum \infty (- \frac{5}{6})^{k}

\frac{6}{11}

Dezimale

0.54545 \dots

Schritte zur Lösung

k = 0 \sum \infty (- \frac{5}{6})^{k}

Geometrischen Test der Reihe anwenden:

\frac{6}{11}

= \frac{6}{11}

n = 1 \sum \infty (\frac{1}{100})^{n}

n = 0 \sum \infty \frac{n}{n ^{3}}

n = 6 \sum \infty ln (\frac{n}{3})

n = 1 \sum \infty e^{\frac{1}{n ^{2}}}

n = 1 \sum \infty 2 (\frac{1}{4})^{n - 1}