What is the derivative of 2/(x+8) ?

The derivative of 2/(x+8) is -2/((x+8)^2)

What is the first derivative of 2/(x+8) ?

The first derivative of 2/(x+8) is -2/((x+8)^2)

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\frac{d}{d x} (\frac{2}{x + 8})

- \frac{2}{( x + 8 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2}{x + 8})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{x + 8})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((x + 8)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 8 ) ^{2}} \frac{d}{d x} (x + 8)

= - \frac{1}{( x + 8 ) ^{2}} \frac{d}{d x} (x + 8)

\frac{d}{d x} (x + 8) = 1

= 2 (- \frac{1}{( x + 8 ) ^{2}} \cdot 1)

Simplify

2 (- \frac{1}{( x + 8 ) ^{2}} \cdot 1) : - \frac{2}{( x + 8 ) ^{2}}

= - \frac{2}{( x + 8 ) ^{2}}

What is the derivative of 2/(x+8) ?
The derivative of 2/(x+8) is -2/((x+8)^2)
What is the first derivative of 2/(x+8) ?
The first derivative of 2/(x+8) is -2/((x+8)^2)