sum from n=1 to infinity of (1+6/n)^n

Lösung

n = 1 \sum \infty (1 + \frac{6}{n})^{n}

divergiert

Schritte zur Lösung

n = 1 \sum \infty (1 + \frac{6}{n})^{n}

Seriendivergenztest anwenden:

divergiert

= divergiert

n = 0 \sum \infty \frac{n ^{2}}{2 n}

n = 5 \sum \infty \frac{1 ^{n}}{n !}

n = 1 \sum \infty \frac{- 1 ^{n}}{e ^{n}}

n = 0 \sum \infty 3 (1 - n)^{- 2}

n = 0 \sum \infty \frac{1}{n}