What is the solution for 9y^'+y=5t^2 ?

The solution for 9y^'+y=5t^2 is y=5(t^2-18(t-9))+(c_{1})/(e^{t/9)}

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9y^'+y=5t^2

9 y^{^{'}} + y = 5 t^{2}

y = 5 (t^{2} - 18 (t - 9)) + \frac{c _{1}}{e ^{\frac{t}{9}}}

Solution steps

9 y^{'} (t) + y = 5 t^{2}

Solve linear ODE:

y = 5 (t^{2} - 18 (t - 9)) + \frac{c _{1}}{e ^{\frac{t}{9}}}

y = 5 (t^{2} - 18 (t - 9)) + \frac{c _{1}}{e ^{\frac{t}{9}}}

What is the solution for 9y^'+y=5t^2 ?
The solution for 9y^'+y=5t^2 is y=5(t^2-18(t-9))+(c_{1})/(e^{t/9)}