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Beliebt Rechnen >

sum from n=1 to infinity of (-1)^nn^5

Lösung

n = 1 \sum \infty (- 1)^{n} n^{5}

Lösung

divergiert

Schritte zur Lösung

n = 1 \sum \infty (- 1)^{n} n^{5}

Seriendivergenztest anwenden:

divergiert

= divergiert

Beliebte Beispiele

sum from n=0 to infinity of (14)/(14+n)

n = 0 \sum \infty \frac{14}{14 + n}

sum from k=0 to infinity of (-5/8)^k

k = 0 \sum \infty (- \frac{5}{8})^{k}

sum from n=1 to infinity of (1-n)/(n^2)

n = 1 \sum \infty \frac{1 - n}{n ^{2}}

sum from n=0 to infinity of-ln(3-n)

n = 0 \sum \infty - ln (3 - n)

sum from n=1 to infinity of (0.6)^n

n = 1 \sum \infty (0.6)^{n}