What is the tangent of y=x^2-5,(-5,20) ?

The tangent of y=x^2-5,(-5,20) is y=-10x-30

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tangent of y=x^2-5,(-5,20)

tangent of

y = x^{2} - 5, (- 5, 20)

y = - 10 x - 30

Solution steps

Find the slope of

y = x^{2} - 5 : \frac{d y}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 10

Find the line with slope m=

- 10

and passing through

(- 5, 20) : y = - 10 x - 30

y = - 10 x - 30

What is the tangent of y=x^2-5,(-5,20) ?
The tangent of y=x^2-5,(-5,20) is y=-10x-30