What is the derivative of y= 4/3 (2x-1)^3 ?

The derivative of y= 4/3 (2x-1)^3 is 8(2x-1)^2

What is the first derivative of y= 4/3 (2x-1)^3 ?

The first derivative of y= 4/3 (2x-1)^3 is 8(2x-1)^2

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derivative of

y = \frac{4}{3} (2 x - 1)^{3}

8 (2 x - 1)^{2}

Solution steps

\frac{d}{d x} (\frac{4}{3} (2 x - 1)^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{4}{3} \frac{d}{d x} ((2 x - 1)^{3})

Apply the chain rule:

3 (2 x - 1)^{2} \frac{d}{d x} (2 x - 1)

= 3 (2 x - 1)^{2} \frac{d}{d x} (2 x - 1)

\frac{d}{d x} (2 x - 1) = 2

= \frac{4}{3} \cdot 3 (2 x - 1)^{2} \cdot 2

Simplify

\frac{4}{3} \cdot 3 (2 x - 1)^{2} \cdot 2 : 8 (2 x - 1)^{2}

= 8 (2 x - 1)^{2}

What is the derivative of y= 4/3 (2x-1)^3 ?
The derivative of y= 4/3 (2x-1)^3 is 8(2x-1)^2
What is the first derivative of y= 4/3 (2x-1)^3 ?
The first derivative of y= 4/3 (2x-1)^3 is 8(2x-1)^2