sum from n=1 to infinity of (cos(14))^n

Lösung

n = 1 \sum \infty (cos (14))^{n}

konvergiert

Schritte zur Lösung

n = 1 \sum \infty (cos (14))^{n}

n = k \sum \infty (a_{n}) = n = 0 \sum \infty (a_{n}) - a_{0} - a_{1} - \dots a_{k - 1}

= n = 0 \sum \infty (cos (14))^{n} - (cos (14))^{0}

n = 0 \sum \infty (cos (14))^{n} =

konvergiert

= konvergiert - (cos (14))^{0}

= konvergiert

n = 1 \sum \infty \frac{- 1 ^{n - 1}}{n}

n = 2 \sum \infty \frac{n}{n ^{2} - 2}

n = 0 \sum \infty (\frac{5}{2})^{n - 1}

n = 1 \sum \infty n^{3} \frac{1}{n !}

n = 2 \sum \infty \frac{9 n}{ln ( n )}