y^'=e^{x-y},y(0)=0

Lösung

y^{^{'}} = e^{x - y}, y (0) = 0

y = x

Schritte zur Lösung

y^{'} (x) = e^{x - y}

Solve separable ODE:

y = x

y = x

1 - \frac{1}{y ^{2} - 4 y + 4} y^{^{'}} = 0

y^{^{'}} = (y^{2} + y^{2} cos (x))^{2}

(4 x - 8) d x - (6 y - 10) d y = 0

\frac{d x}{d t} = 80 - \frac{x}{100}

y^{^{'}} = x y^{2} - x, y (1) = 2