y^'=cos(x)tan(y)

Lösung

y^{^{'}} = cos (x) tan (y)

y = arcsin (e^{s i n (x) + c_{1}}) + 2 πn, y = π + arcsin (- e^{s i n (x) + c_{1}}) + 2 πn

Schritte zur Lösung

y^{'} (x) = cos (x) tan (y)

Solve separable ODE:

y = arcsin (e^{s i n (x) + c_{1}}) + 2 πn, y = π + arcsin (- e^{s i n (x) + c_{1}}) + 2 πn

y = arcsin (e^{s i n (x) + c_{1}}) + 2 πn, y = π + arcsin (- e^{s i n (x) + c_{1}}) + 2 πn

y e^{y} d y + x d x = 0

\frac{d y}{d x} = \frac{2 x}{- 8 y - 10}, y (0) = - 8

y^{^{'}} = x e^{y - x}

x y^{2} d x + x d y = 0

\frac{d y}{d x} = x^{2} y + 4 x^{2}