What is the solution for (dy)/(dx)+3x^2y=sin(x)e^{-x^3},y(0)=1 ?

The solution for (dy)/(dx)+3x^2y=sin(x)e^{-x^3},y(0)=1 is y=-(cos(x))/(e^{x^3)}+2/(e^{x^3)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(dy)/(dx)+3x^2y=sin(x)e^{-x^3},y(0)=1

\frac{d y}{d x} + 3 x^{2} y = sin (x) e^{- x^{3}}, y (0) = 1

y = - \frac{cos ( x )}{e ^{x^{3}}} + \frac{2}{e ^{x^{3}}}

Solution steps

\frac{d y}{d x} + 3 x^{2} y = sin (x) e^{- x^{3}}

Solve linear ODE:

y = - \frac{cos ( x )}{e ^{x^{3}}} + \frac{2}{e ^{x^{3}}}

y = - \frac{cos ( x )}{e ^{x^{3}}} + \frac{2}{e ^{x^{3}}}

What is the solution for (dy)/(dx)+3x^2y=sin(x)e^{-x^3},y(0)=1 ?
The solution for (dy)/(dx)+3x^2y=sin(x)e^{-x^3},y(0)=1 is y=-(cos(x))/(e^{x^3)}+2/(e^{x^3)}