x^'=-5x

Lösung

x^{^{'}} = - 5 x

x = e^{- 5 t + c_{1}}

Schritte zur Lösung

x^{'} (t) = - 5 x

Solve separable ODE:

x = e^{- 5 t + c_{1}}

x = e^{- 5 t + c_{1}}

\frac{d y}{d x} - \frac{y}{1 - x ^{2}} = 0

\frac{d y}{d x} = 5 x sec (y)

3 x (y^{2} + 1) d x + y (x^{2} + 1) d y = 0

\frac{d y}{d x} = - y, y (0) = 1

y^{2} y^{^{'}} - cos (x) = 0