x^'=2x+4

Lösung

x^{^{'}} = 2 x + 4

x = e^{2 t + c_{1}} - 2

Schritte zur Lösung

x^{'} (t) = 2 x + 4

Solve separable ODE:

x = e^{2 t + c_{1}} - 2

x = e^{2 t + c_{1}} - 2

\frac{d y}{d x} = \frac{3 - y}{x}

\frac{d}{d x} ((y - 1)^{2}) = 4 (x + 2)

y^{^{'}} = 1 - 2 cos (y)

\frac{d y}{d x} = - y sin (x)

\frac{d y}{d x} = 2 y (1 - \frac{y}{5})