y^'=e^ysin(x)

Lösung

y^{^{'}} = e^{y} sin (x)

y = - ln (cos (x) - c_{1})

Schritte zur Lösung

y^{'} (x) = e^{y} sin (x)

Solve separable ODE:

y = - ln (cos (x) - c_{1})

y = - ln (cos (x) - c_{1})

\frac{d x}{d y} = \frac{y}{x}

10 y^{2} (x d y + y d x) = y d x - x d y

\frac{d}{d x} (2 y^{2}) = 3 - x

y^{^{'}} = e^{y} x^{6}

\frac{d y}{d x} = 64 y x^{15}