x^'+7x=0

Lösung

x^{^{'}} + 7 x = 0

x = e^{- 7 t + c_{1}}

Schritte zur Lösung

x^{'} (t) + 7 x = 0

Solve separable ODE:

x = e^{- 7 t + c_{1}}

x = e^{- 7 t + c_{1}}

\frac{d}{d x} (2 x y) - y^{2} = 1

2 x \frac{d y}{d x} - x y = - x y^{3}

3 x y^{^{'}} + 5 y = 10

x^{^{'}} + c x = a

\frac{d p}{d t} = c (1 - p)