y^'=-(3x^2)/(4y)

Lösung

y^{^{'}} = - \frac{3 x ^{2}}{4 y}

y = - \frac{x ^{3}}{2} + c_{1}, y = - - \frac{x ^{3}}{2} + c_{1}

Schritte zur Lösung

y^{'} (x) = - \frac{3 x ^{2}}{4 y}

Solve separable ODE:

y = - \frac{x ^{3}}{2} + c_{1}, y = - - \frac{x ^{3}}{2} + c_{1}

y = - \frac{x ^{3}}{2} + c_{1}, y = - - \frac{x ^{3}}{2} + c_{1}

y^{^{'}} = y cos (5 x), y (0) = 1

y^{^{'}} = - 2 - y + y^{2}

\frac{d y}{d t} = \frac{t ^{2}}{y}

y^{^{'}} = cos (x) (3 y - 1)

ln (\frac{d y}{d x}) = a x + b y