y^' 2/x y=4x

Lösung

y^{^{'}} \frac{2}{x} y = 4 x

y = \frac{4 x ^{3}}{3} + c_{1}, y = - \frac{4 x ^{3}}{3} + c_{1}

Schritte zur Lösung

y^{'} (x) \frac{2}{x} y = 4 x

Solve separable ODE:

y = \frac{4 x ^{3}}{3} + c_{1}, y = - \frac{4 x ^{3}}{3} + c_{1}

y = \frac{4 x ^{3}}{3} + c_{1}, y = - \frac{4 x ^{3}}{3} + c_{1}

y^{2} y^{^{'}} - x^{2} = 0, y (- 2) = - 2

y^{^{'}} + y^{2} - y = 0, y (2) = 4

\frac{d y}{d x} + y = e^{- 2}

(1 + x^{2}) \frac{d y}{d x} (2 x y) = - x

2 \frac{d y}{d t} + 4 y = 6