y^'=-2.1(y-10)

Lösung

y^{^{'}} = - 2.1 (y - 10)

y = e^{- 2.1 t + c_{1}} + 10

Schritte zur Lösung

y^{'} (t) = - 2.1 (y - 10)

Solve separable ODE:

y = e^{- 2.1 t + c_{1}} + 10

y = e^{- 2.1 t + c_{1}} + 10

\frac{d r}{4 r} = - t d t

y^{^{'}} = - 3 x^{2} (y + 1)^{2}

\frac{d y}{d x} = 10 e^{5 x - 3 y}, y (0) = 0

y^{^{'}} + \frac{4}{x} y = 0

(1 + x) y d x + x d y = 0