d/(dθ)(r(θ))r(θ)= 3/(sqrt(17-θ))

Lösung

\frac{d r}{d θ} r = \frac{3}{17 - θ}

r (θ) = - 6 17 - θ + c_{1}, r (θ) = - - 6 17 - θ + c_{1}

Schritte zur Lösung

\frac{d}{d θ} ((r (θ)) r (θ)) = \frac{3}{17 - θ}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

r (θ) r (θ) = \int \frac{3}{17 - θ} d θ

\int \frac{3}{17 - θ} d θ = - 6 17 - θ + c_{1}

r (θ) r (θ) = - 6 17 - θ + c_{1}

Isoliere

r (θ) : r (θ) = - 6 17 - θ + c_{1}, r (θ) = - - 6 17 - θ + c_{1}

r (θ) = - 6 17 - θ + c_{1}, r (θ) = - - 6 17 - θ + c_{1}

\frac{d x}{d t} = 75 - \frac{x}{100}, x = 4000, t = 0

(2 y - 2) \frac{d y}{d x} = 3 x^{2} + 4 x + 2, y (1) = - 2

d s + cos (2 t) d t = 0

m d n + n^{2} d m = 0

3 x + 20 y y^{^{'}} = 0, y (2) = 5