y^'=6y-15

Lösung

y^{^{'}} = 6 y - 15

y = \frac{e ^{6 t + c_{1}}}{2} + \frac{5}{2}

Schritte zur Lösung

y^{'} (t) = 6 y - 15

Solve separable ODE:

y = \frac{e ^{6 t + c_{1}}}{2} + \frac{5}{2}

y = \frac{e ^{6 t + c_{1}}}{2} + \frac{5}{2}

\frac{d y}{d x} x = y^{4}

\frac{d x}{d t} = t x + 4 x + 3 t + 12

\frac{d y}{d x} = \frac{1}{x ^{2} y ^{4}}

y^{^{'}} = \frac{2 x}{y}, y (1) = - 2

y^{^{'}} + x^{2} y = 2 x^{2}