y^'= 1/2 y^3

Lösung

y^{^{'}} = \frac{1}{2} y^{3}

y = - \frac{1}{t + c _{1}}, y = - - \frac{1}{t + c _{1}}

Schritte zur Lösung

y^{'} (t) = \frac{1}{2} y^{3}

Solve separable ODE:

y = - \frac{1}{t + c _{1}}, y = - - \frac{1}{t + c _{1}}

y = - \frac{1}{t + c _{1}}, y = - - \frac{1}{t + c _{1}}

y^{^{'}} \cdot tan (x) - y = - 2

\frac{d y}{d x} + 6 y = 1

y^{^{'}} = 2 x cos^{2} (y)

y^{^{'}} - 12 x y = 0

\frac{d y}{d x} = y (5 x^{2} + 5)