y^'=tan(x)cot(y)

Lösung

y^{^{'}} = tan (x) cot (y)

y = arccos (c_{1} cos (x)) + 2 πn, y = - arccos (c_{1} cos (x)) + 2 πn

Schritte zur Lösung

y^{'} (x) = tan (x) cot (y)

Solve separable ODE:

y = arccos (c_{1} cos (x)) + 2 πn, y = - arccos (c_{1} cos (x)) + 2 πn

y = arccos (c_{1} cos (x)) + 2 πn, y = - arccos (c_{1} cos (x)) + 2 πn

\frac{d y}{d x} = 10 + 3 y, y (0) = - 3

y^{^{'}} = \frac{x ^{2} + 3}{4 y ^{3}}

x y^{^{'}} - y = x y

d y = (y^{2} - 4) d x

h^{^{'}} = \frac{2 h}{x ln ( x )}