y^'=25+y^2,y(0)=5tan(5x)

Lösung

y^{^{'}} = 25 + y^{2}, y (0) = 5 tan (5 x)

y = 5 tan (5 x + c_{1})

Schritte zur Lösung

y^{'} (x) = 25 + y^{2}

Solve separable ODE:

y = 5 tan (5 x + c_{1})

y = 5 tan (5 x + c_{1})

\frac{d y}{d x} = \frac{x ^{3} y ^{3}}{x + 3}

y^{^{'}} - 2 x y = 3 x

\frac{d y}{d x} = \frac{1}{x} (y^{2} + y), y (1) = 1

e^{- x} y^{^{'}} + y = 1

\frac{d y}{d x} = (1 - x^{2}) y