(y-1)/(5+x^2)dy=y^2dx

解答

\frac{y - 1}{5 + x ^{2}} d y = y^{2} d x

y = - \frac{1}{W ( - \frac{1}{e ^{\frac{x ^{3} + 15 x + c _{1}}{3}}} )}

求解步骤

\frac{y - 1}{5 + x ^{2}} d y = y^{2} d x

求解可分离方程:

y = - \frac{1}{W ( - \frac{1}{e ^{\frac{x ^{3} + 15 x + c _{1}}{3}}} )}

y = - \frac{1}{W ( - \frac{1}{e ^{\frac{x ^{3} + 15 x + c _{1}}{3}}} )}

y^{^{'}} = 7 x y

R = \frac{d R}{d t}

y^{^{'}} = \frac{y}{x + 1}

y^{^{'}} = \frac{y}{x} \cdot ln (y)

\frac{d p}{d t} = 0.5 p - 450