y^'=(ty^2)/(t^2+e)

Lösung

y^{^{'}} = \frac{t y ^{2}}{t ^{2} + e}

y = - \frac{2}{ln ( t ^{2} + e ) + c _{1}}

Schritte zur Lösung

y^{'} (t) = \frac{t y ^{2}}{t ^{2} + e}

Solve separable ODE:

y = - \frac{2}{ln ( t ^{2} + e ) + c _{1}}

y = - \frac{2}{ln ( t ^{2} + e ) + c _{1}}

y^{^{'}} = 1 + y + y^{2}

\frac{d y}{d x} = \frac{x ^{3}}{2 y ^{2}}

\frac{d y}{d x} = 2 x^{2} y^{2}

(2 + x) d y - y d x = 0

(y + 1) d x + (6 x - 1) d y = 0