(5+x)y^'=2y

Lösung

(5 + x) y^{^{'}} = 2 y

y = 25 e^{c_{1}} + 10 e^{c_{1}} x + e^{c_{1}} x^{2}

Schritte zur Lösung

(5 + x) y^{'} (x) = 2 y

Solve separable ODE:

y = 25 e^{c_{1}} + 10 e^{c_{1}} x + e^{c_{1}} x^{2}

y = 25 e^{c_{1}} + 10 e^{c_{1}} x + e^{c_{1}} x^{2}

(1 - y^{2}) d x = - (x y - y) d y

e^{- y} + e^{- y} y^{^{'}} = 1

y^{^{'}} = - \frac{1}{y}

[1 + t^{2}] \frac{d y}{d t} = 1 + y^{2}

y^{^{'}} = x^{2} y, y (0) = 1