y^'-((2x)/(1+x^2))y=0,y(0)=3

Lösung

y^{^{'}} - (\frac{2 x}{1 + x ^{2}}) y = 0, y (0) = 3

y = 3 (x^{2} + 1)

Schritte zur Lösung

y^{'} (x) - (\frac{2 x}{1 + x ^{2}}) y = 0

Solve separable ODE:

y = 3 (x^{2} + 1)

y = 3 (x^{2} + 1)

\frac{d y}{y + 2} = d x

\frac{d x}{x} = \frac{d z}{z}

\frac{d y}{d x} + b y - a = 0

d x + (\frac{y - 1}{x ^{2}})^{3} d y = 0

y^{^{'}} = 2 t y cos (t^{2})