y^'-e^{3x+2y}=0

Lösung

y^{^{'}} - e^{3 x + 2 y} = 0

y = - \frac{ln ( - \frac{2}{3} e ^{3 x} - c _{1} )}{2}

Schritte zur Lösung

y^{'} (x) - e^{3 x + 2 y} = 0

Solve separable ODE:

y = - \frac{ln ( - \frac{2}{3} e ^{3 x} - c _{1} )}{2}

y = - \frac{ln ( - \frac{2}{3} e ^{3 x} - c _{1} )}{2}