xy^'=y,y(a)=b

Lösung

x y^{^{'}} = y, y (a) = b

y = \frac{b x}{a}

Schritte zur Lösung

x y^{'} (x) = y

Solve separable ODE:

y = \frac{b x}{a}

y = \frac{b x}{a}

\frac{d y}{d x} = 2 x (1 - y)

y^{^{'}} = e^{3 x - 2 y} + x^{2} e^{- 2 y}

\frac{d t}{d x} + \frac{3}{x} = - \frac{1}{x ^{2}}

\frac{d y}{d x} = 0.06 - \frac{y}{1350}

y^{^{'}} - 5 y = 10, y (0) = 0