(e^xy)y^'=e^{-y}+e^{-2x-y}

Lösung

(e^{x} y) y^{^{'}} = e^{- y} + e^{- 2 x - y}

y = W (\frac{- \frac{3}{e ^{x}} - \frac{1}{e ^{3 x}} + c _{1}}{3 e}) + 1

Schritte zur Lösung

(e^{x} y) y^{'} (x) = e^{- y} + e^{- 2 x - y}

Solve separable ODE:

y = W (\frac{- \frac{3}{e ^{x}} - \frac{1}{e ^{3 x}} + c _{1}}{3 e}) + 1

y = W (\frac{- \frac{3}{e ^{x}} - \frac{1}{e ^{3 x}} + c _{1}}{3 e}) + 1

\frac{d y}{d x} = - \frac{0.6}{cos ( y )}

e^{y} \frac{d y}{d x} - x^{2} = 0

\frac{d x}{d y} = e^{x + y}

\frac{d y}{d x} = (\frac{5 y}{x})

y^{^{'}} - 2 y + 3 = 0