y^'=cos(t)*y

Lösung

y^{^{'}} = cos (t) \cdot y

y = e^{s i n (t) + c_{1}}

Schritte zur Lösung

y^{'} (t) = cos (t) \cdot y

Solve separable ODE:

y = e^{s i n (t) + c_{1}}

y = e^{s i n (t) + c_{1}}

y^{2} sec (2 x) \frac{d y}{d x} = 1, y (0) = 0

x y^{3} d x + e^{x^{3}} d y = 0

\frac{d y}{d x} = \frac{y sin ( x )}{y + 1}

y y^{^{'}} + 2 x^{2} = 0

\frac{d y}{d x} + (2 y^{2}) = 2 y