x^{1/3}y^'+y=0

Lösung

x^{\frac{1}{3}} y^{^{'}} + y = 0

y = e^{- \frac{3}{2} x^{\frac{2}{3}} + c_{1}}

Schritte zur Lösung

x^{\frac{1}{3}} y^{'} (x) + y = 0

Solve separable ODE:

y = e^{- \frac{3}{2} x^{\frac{2}{3}} + c_{1}}

y = e^{- \frac{3}{2} x^{\frac{2}{3}} + c_{1}}

y^{^{'}} = x y^{3} \cdot (1 + x^{2})^{(\frac{- 1}{2})}

3 y^{2} d y - t d t = 0

y^{^{'}} + 21 x^{2} y = 21 x^{2}

f^{^{'}} (x) = 7 f (x)

y^{^{'}} = 8 x (y^{2} + 1)