y^'= y/(x+sqrt(x))

Lösung

y^{^{'}} = \frac{y}{x + x}

y = e^{c_{1}} x + 2 e^{c_{1}} x + e^{c_{1}}

Schritte zur Lösung

y^{'} (x) = \frac{y}{x + x}

Solve separable ODE:

y = e^{c_{1}} x + 2 e^{c_{1}} x + e^{c_{1}}

y = e^{c_{1}} x + 2 e^{c_{1}} x + e^{c_{1}}

\frac{d}{d x} (x \cdot cos (y)) = 1

y^{^{'}} = \frac{x y}{y + 1}

y^{^{'}} = u - y

y^{^{'}} = y^{2} + 2 y + 1

\frac{y ^{^{'}}}{x} = 4 y