What is the solution for (3y^2-x^2)/(y^5)(dy)/(dx)+x/(2y^4)=0 ?

The solution for (3y^2-x^2)/(y^5)(dy)/(dx)+x/(2y^4)=0 is

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(3y^2-x^2)/(y^5)(dy)/(dx)+x/(2y^4)=0

\frac{3 y ^{2} - x ^{2}}{y ^{5}} \frac{d y}{d x} + \frac{x}{2 y ^{4}} = 0

y = \frac{- 3 + 2 c _{1} x ^{2} + 9}{2 c _{1}}, y = - \frac{- 3 + 2 c _{1} x ^{2} + 9}{2 c _{1}}, y = - \frac{2 c _{1} x ^{2} + 9 + 3}{2 c _{1}}, y = - - \frac{2 c _{1} x ^{2} + 9 + 3}{2 c _{1}}

Solution steps

\frac{3 y ^{2} - x ^{2}}{y ^{5}} \frac{d y}{d x} + \frac{x}{2 y ^{4}} = 0

Solve exact ODE:

y = \frac{- 3 + 2 c _{1} x ^{2} + 9}{2 c _{1}}, y = - \frac{- 3 + 2 c _{1} x ^{2} + 9}{2 c _{1}}, y = - \frac{2 c _{1} x ^{2} + 9 + 3}{2 c _{1}}, y = - - \frac{2 c _{1} x ^{2} + 9 + 3}{2 c _{1}}

y = \frac{- 3 + 2 c _{1} x ^{2} + 9}{2 c _{1}}, y = - \frac{- 3 + 2 c _{1} x ^{2} + 9}{2 c _{1}}, y = - \frac{2 c _{1} x ^{2} + 9 + 3}{2 c _{1}}, y = - - \frac{2 c _{1} x ^{2} + 9 + 3}{2 c _{1}}

What is the solution for (3y^2-x^2)/(y^5)(dy)/(dx)+x/(2y^4)=0 ?
The solution for (3y^2-x^2)/(y^5)(dy)/(dx)+x/(2y^4)=0 is