y^'=(x^4+7)(cos(y))^2

Lösung

y^{^{'}} = (x^{4} + 7) (cos (y))^{2}

y = arctan (\frac{x ^{5}}{5} + 7 x + c_{1}) + πn

Schritte zur Lösung

y^{'} (x) = (x^{4} + 7) (cos (y))^{2}

Solve separable ODE:

y = arctan (\frac{x ^{5}}{5} + 7 x + c_{1}) + πn

y = arctan (\frac{x ^{5}}{5} + 7 x + c_{1}) + πn

y^{^{'}} = r \cdot y \cdot (1 - \frac{y}{k})

2 y \cdot e^{y^{2}} \cdot y^{^{'}} = 2 x + 3 x

y \cdot y^{^{'}} - x = 0

t y^{^{'}} + 2 y = \frac{1}{2}

y^{^{'}} = (1 - 5 x) y^{2}, y (0) = - \frac{1}{8}