3e^ttan(y)dt+(2-e^t)sec^2(y)dy=0

Lösung

3 e^{t} tan (y) d t + (2 - e^{t}) sec^{2} (y) d y = 0

y = arctan (8 e^{c_{1}} - 12 e^{c_{1} + t} + 6 e^{c_{1} + 2 t} - e^{c_{1} + 3 t}) + πn

Schritte zur Lösung

3 e^{t} tan (y) d t + (2 - e^{t}) sec^{2} (y) d y = 0

Solve separable ODE:

y = arctan (8 e^{c_{1}} - 12 e^{c_{1} + t} + 6 e^{c_{1} + 2 t} - e^{c_{1} + 3 t}) + πn

y = arctan (8 e^{c_{1}} - 12 e^{c_{1} + t} + 6 e^{c_{1} + 2 t} - e^{c_{1} + 3 t}) + πn

y^{^{'}} = 2 x^{3} y

y^{^{'}} y = t, y (3) = - 3

\frac{d x}{d y} = e^{2 x + 3 y}, x (0) = 1

(3 x - 2) d x + (4 y + b) d y = 0

y^{^{'}} = \frac{( 3 t ^{2} )}{4 + 2 y}