integral of (7-6x^3+4x^6)/(x^6)

解

\int \frac{7 - 6 x ^{3} + 4 x ^{6}}{x ^{6}} d x

- \frac{7}{5 x ^{5}} + \frac{3}{x ^{2}} + 4 x + C

解答ステップ

\int \frac{7 - 6 x ^{3} + 4 x ^{6}}{x ^{6}} d x

拡張

\frac{7 - 6 x ^{3} + 4 x ^{6}}{x ^{6}} : \frac{7}{x ^{6}} - \frac{6}{x ^{3}} + 4

= \int \frac{7}{x ^{6}} - \frac{6}{x ^{3}} + 4 d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{7}{x ^{6}} d x - \int \frac{6}{x ^{3}} d x + \int 4 d x

\int \frac{7}{x ^{6}} d x = - \frac{7}{5 x ^{5}}

\int \frac{6}{x ^{3}} d x = - \frac{3}{x ^{2}}

\int 4 d x = 4 x

= - \frac{7}{5 x ^{5}} - (- \frac{3}{x ^{2}}) + 4 x

簡素化

= - \frac{7}{5 x ^{5}} + \frac{3}{x ^{2}} + 4 x

定数を解答に追加する

= - \frac{7}{5 x ^{5}} + \frac{3}{x ^{2}} + 4 x + C