1*y^'-y=200

Lösung

1 \cdot y^{^{'}} - y = 200

y = e^{t + c_{1}} - 200

Schritte zur Lösung

1 \cdot y^{'} (t) - y = 200

Solve separable ODE:

y = e^{t + c_{1}} - 200

y = e^{t + c_{1}} - 200

1 - x^{2} = - \frac{4 x y d y}{d x}

\frac{d y}{d x} = 2 + 3 y

\frac{d y}{d x} + 3 x y = 10 x, y (0) = 5

y^{^{'}} = x^{2} y + x^{2}

y^{^{'}} = y - y^{3}, y (0) = 2