y^'=-(1/2)y^2,y(0)=0.5

Lösung

y^{^{'}} = - (\frac{1}{2}) y^{2}, y (0) = 0.5

y = \frac{2}{t + 4}

Schritte zur Lösung

y^{'} (t) = - (\frac{1}{2}) y^{2}

Solve separable ODE:

y = \frac{2}{t + 4}

y = \frac{2}{t + 4}

3 y d x + 8 x d y = 0

y^{^{'}} = 11 e^{x} e^{- y}

\frac{d x}{d t} = \frac{2}{x e ^{t + 9 x}}

x \cdot y^{^{'}} ln (x) = x \cdot y

\frac{d y}{d x} = \frac{x ( 1 - y )}{x ^{2} - 2}