(y^')/x+2y=4

Lösung

\frac{y ^{^{'}}}{x} + 2 y = 4

y = - e^{- x^{2} - c_{1}} + 2

Schritte zur Lösung

\frac{y ^{'} ( x )}{x} + 2 y = 4

Solve separable ODE:

y = - e^{- x^{2} - c_{1}} + 2

y = - e^{- x^{2} - c_{1}} + 2

\frac{d x}{d y} + 3 x = 25

y^{^{'}} + \frac{y}{5} = 3, y (- 3) = 0

y^{^{'}} + \frac{y}{- 10} = 0

x \cdot y^{^{'}} = 2 y ln (y)

y^{^{'}} = 7 x^{6} e^{- y}