y^'=(2/t-t)y

Lösung

y^{^{'}} = (\frac{2}{t} - t) y

y = e^{- \frac{t ^{2}}{2} + c_{1}} t^{2}

Schritte zur Lösung

y^{'} (t) = (\frac{2}{t} - t) y

Solve separable ODE:

y = e^{- \frac{t ^{2}}{2} + c_{1}} t^{2}

y = e^{- \frac{t ^{2}}{2} + c_{1}} t^{2}

(ux)^{2} u d x + x d u + x^{2} + (x) (ux) + (ux)^{2} = 0

\frac{d r}{d t} = - r

y = x \frac{d y}{d x}

y^{^{'}} - 2 e^{x} y = - 2 e^{x}

y^{^{'}} = \frac{x ( x ^{2} + 1 )}{( 4 y ^{2} )}