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Beliebt Rechnen >

y^'=1+0.01y^2

Lösung

y^{^{'}} = 1 + 0.01 y^{2}

Lösung

y = \frac{tan ( \frac{t + c _{1}}{10} )}{0.1}

Schritte zur Lösung

y^{'} (t) = 1 + 0.01 y^{2}

Solve separable ODE:

y = \frac{tan ( \frac{t + c _{1}}{10} )}{0.1}

y = \frac{tan ( \frac{t + c _{1}}{10} )}{0.1}

Graph

Beliebte Beispiele

(dy)/(dx)=(y+1)

\frac{d y}{d x} = (y + 1)

y*ln(x)(dy}{dx}=(\frac{y+1)/x)^2

y \cdot ln (x) \frac{d y}{d x} = (\frac{y + 1}{x})^{2}

(dN)/(dt)=k(1-N)^2

\frac{d N}{d t} = k (1 - N)^{2}

(dt)/(dx)=(8t)/(x+5)

\frac{d t}{d x} = \frac{8 t}{x + 5}

(dx)/(dt)=75-x/(100),x=2000,t=0

\frac{d x}{d t} = 75 - \frac{x}{100}, x = 2000, t = 0