x^'=nx^2

Lösung

x^{^{'}} = n x^{2}

x = - \frac{1}{n t + c _{1}}

Schritte zur Lösung

x^{'} (t) = n x^{2}

Solve separable ODE:

x = - \frac{1}{n t + c _{1}}

x = - \frac{1}{n t + c _{1}}

x \frac{d y}{d x} + y = \frac{5}{y ^{2}}

\frac{d y}{d x} x^{2} + 4 x y = y

y^{^{'}} - y sin (3 x) = 0

d y = \frac{( y + 4 )}{x + 5} d x

\frac{d y}{d x} y = \frac{1 - 2 x ^{2}}{x ^{4} - 2 x ^{2} + 6}